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grandymaker [24]
3 years ago
10

A pair of supplementary angles are_____________. A. A and BB. B and DC. C and E​

Mathematics
1 answer:
shutvik [7]3 years ago
4 0

A pair of supplementary angles are C and E. We know that B, D, and E are all congruent, and can see that both C and B, and C and D would form supplementary angles. So, we can also use E to form supplementary angles.

Hope this helps! :)

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Solve the following quadratic equations by any method. The solutions are:
Nataly_w [17]

Answer:

Option C .

Step-by-step explanation:

We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

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Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow f(x) = 0\\

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Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

\longrightarrow x^2-8x - 4x +32=0\\

\longrightarrow x(x-8)-4(x-8)=0\\

\longrightarrow (x-8)(x-4)=0\\

Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow x - 8 = 0\\ \qquad x -4=0

\longrightarrow x = 8 \qquad x = 4

\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}

<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>

8 0
2 years ago
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Tanya [424]

5

Step-by-step explanation:

your answer is 5 the greatest common factor is 5

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15= 5

5 0
3 years ago
Can someone actually help me and go to my recently asked questions
Annette [7]

Answer:

Um... Sure?

Step-by-step explanation:

Okay, 'll go to your questions...

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Answer:

d

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P = Present value  

R = interest rate  

N = number of years

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d. . 6000x (1 + 0.05/12)^60 =6630.47

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Delvig [45]

y = 3/2x is the answer for this problem.

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