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3 years ago

11

Which expression is equivalent to 9x + 54 – 27 + 3y + 6y?

1 answer:

sammy [17]3 years ago

5 0

9y+9x=27
x+y=3

<em><u /></em><u>Answer:</u> <em>x</em>+<em>y</em>=3

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Sam wants to buy 8 pencils and 6 pens, which cost a total of $8.50. He realizes he doesn't have enough cash and instead takes on

Diano4ka-milaya [45]

X = pencils, y = pens

8x + 6y = 8.50
4x + 4y = 5.....multiply by -2
----------------
8x + 6y = 8.50
-8x - 8y = -10 (result of multiplying by -2)
-----------------add
-2y = - 1.50
y = -1.50 / -2
y = 0.75 <=== pens cost 0.75

4x + 4y = 5
4x + 4(0.75) = 5
4x + 3 = 5
4x = 5 - 3
4x = 2
x = 2/4
x = 0.50 <== pencils cost 0.50

8 0

3 years ago

Elza [17]

Answer:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

Step-by-step explanation:

Required

Which equals $x = 4$

$(a)\ 2x + 6 = 2$

Collect like terms

$2x = 2 - 6$

$2x = -4$

Divide both sides by 2

$x = -2$

$(b)\ 2x - 9 = -1$

Collect like terms

$2x = -1 + 9$

$2x = 8$

Divide both sides by 2

$x = 4$

$(c)\ -2x + 12 = 4$

Collect like terms

$-2x =- 12 + 4$

$-2x =-8$

Divide both sides by -2

$x = 4$

$(d)\ 2(x + 2) = 10$

Divide both sides by 2

$x + 2 =5$

Collect like terms

$x = 5-2$

$x = 3$

$(e)\ 2(x - 10) = -12$

Divide both sides by 2

$x - 10 = -6$

Collect like terms

$x = 10 - 6$

$x = 4$

Hence, the equations with the required solution are:

$(b)\ 2x - 9 = -1$

$(c)\ -2x + 12 = 4$

$(e)\ 2(x - 10) = -12$

3 0

3 years ago

Please help! Thank you :) also don't spam for points I know a moderator

dybincka [34]

Answer:

1) True

2) False

3) True

4) True

5) False

4 0

2 years ago

OMG last one please help

vichka [17]

Answer:

m<D = 14

Step-by-step explanation:

Exterior angles thm:

83 + 6x - 4 = 21x + 4

6x + 79 = 21x + 4

6x - 21x = 4 - 79

-15x = -75

x = 5

m<D:

6x - 4

6(3) - 4

18 - 4

14

3 0

3 years ago

What is the solution to q/-7=6?

marta [7]

Answer:

q in (-oo:+oo)

q/(-7) = 6 // - 6

q/(-7)-6 = 0

-1/7*q-6 = 0 // + 6

-1/7*q = 6 // : -1/7

q = 6/(-1/7)

q = -42

q = -42

Hope I was helpful! :)

5 0

3 years ago