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inysia [295]
4 years ago
9

Five different books (A, B, C, D and E) are to be arranged on a shelf. Books C and D are to be arranged first and second startin

g from the right of the shelf. The number of different orders in which books A, B and E may be arranged is
A. 5
B. 3
C. 2
D. 6
Mathematics
1 answer:
vekshin14 years ago
5 0
Your answer would be B.
HOPE THIS HELPS YOU! ^_^
You might be interested in
Jared buys 3 pounds of chicken at $3.15 per pound and 1 pound of broccoli at $1.40 per pound. How much will it cost to make dinn
zaharov [31]

Answer:

Cost of dinner: $10.85

Money to add: $1.40

Step-by-step explanation:

1. Calculate the cost of the chicken and broccoli: 3(3.15)+1(1.40)=$10.85

2. Subtract Jared's money from the cost of dinner: $10.85-$9.45=$1.40

4 0
3 years ago
A square is inscribed in a circle with an area of 10 pi square inches. what is the area of the square
Naddik [55]
We need to determine the radius and diameter of the circle.  If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,

A = 10 pi in^2 = pi*r^2.  Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.

Thus, the diam. of the circle is 2sqrt(10) in.  This diam. has the same length as does the hypotenuse of one of the triangles making up the square.

Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square.  So, 4(10) in^2 = 2x^2.  Then:
                                 40 in^2  = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20).  The area of the square is the square of this result:

Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer).  Compare that to the 10 pi sq in area of the circle (31.42 in^2).
8 0
3 years ago
(3,6) (3,7) (-2,-5) (-9,11) is it a function a relation, or both
amid [387]

It is a relation but not a function

Step-by-step explanation:

Given

(3,6) (3,7) (-2,-5) (-9,11)

First of all we have to define both terms: Relation and Function

A relation is a set of ordered pairs containing one element from each set

A relation can be a function only if there is no repetition in domain i.e. no first element in each ordered pair should be repeated.

In the given set of ordered pairs, they are relation as all the ordered pairs have two values.

While the given relation is not a function, as there is repetition in first elements of two ordered pairs i.e. 3 is repeated in (3,6) (3,7)

Hence,

It is a relation but not a function

Keywords: Functions, Relations

Learn more about functions at:

  • brainly.com/question/13219835
  • brainly.com/question/1836777

#LearnwithBrainly

6 0
4 years ago
How does the area of a circle change if the radius is multiplied by a factor of n, where n is a whole number?
Fantom [35]
Increases but is that what you are asking?
6 0
4 years ago
What is the mean of the set of numbers?
Llana [10]
The mean of your question would be -2.5
3 0
3 years ago
Read 2 more answers
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