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ioda
3 years ago
8

Can you give examples of situations that might be modeled with trigonometric functions? That is, can you give examples of phenom

ena that take on a series of values over and over again?
Mathematics
2 answers:
PIT_PIT [208]3 years ago
7 0

Answer:

There several situations in real life that can be modeled with trigonometric functions. Perhaps one of the most famous examples is a vibrating string, as the ones we can see in music instruments. Also, the behavior of the electric current  is modeled using trigonometric functions, in particular in a circuit with alternate current. Another example is the movement of a pendulum with short oscillations

Step-by-step explanation:

kvasek [131]3 years ago
4 0

Here are your examples

A spring that is bouncing up and down.

An atom or molecule that resonates with a certain frequency.

In fact, anything that resonates: a violin string, a pendulum, the air column in a muffler,.....


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QUESTION 5 Simplify 6 – 4x – 2 + x. <br> 4 + x <br> 4 – 3x <br> 1 <br> 3 – 4x
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6 – 4x – 2 + x.

Combine like terms

= (6 - 2) + (-4x + x)

= 4 - 3x

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A bakery sold 208 chocolate cupcakes in a day, which was 52% of the total number of cupcakes sold that day. How many total cupca
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Step-by-step explanation:

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3 years ago
Helpp the topic is about limits
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Since we want to find the value of <em>k</em><em> </em>where the limit exists, set both equations equal to each other. Then substitute <em>x</em> = -1 in for each equation to find <em>k</em><em>.</em>

<em>kx - 3 =  {x}^{2}  + k</em>

1. Set both equations equal.

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2. Substitute <em>x</em><em> </em>= -1.

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8 0
3 years ago
Zoey invested $230 in an account paying an interest rate of 6.3% compounded daily.
alukav5142 [94]

Answer:

A ≈ $500

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Compounded Interest Rate: A = P(1 + r/n)ⁿˣ

  • A is final amount
  • P is initial (principle) amount
  • r is rate
  • n is number of compounds
  • x is number of years

Step-by-step explanation:

<u>Step 1: Define</u>

P = 230

r = 0.063

n = 365

x = 12

<u>Step 2: Solve for </u><em><u>A</u></em>

  1. Substitute:                    A = 230(1 + 0.063/365)³⁶⁵⁽¹²⁾
  2. Divide:                          A = 230(1 + 0.000173)³⁶⁵⁽¹²⁾
  3. Multiply:                        A = 230(1 + 0.000173)⁴³⁸⁰
  4. Add:                              A = 230(1.00017)⁴³⁸⁰
  5. Exponents:                   A = 230(2.1296)
  6. Multiply:                        A = 489.808
3 0
3 years ago
Read 2 more answers
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