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Delvig [45]
2 years ago
15

Harry earns $45 a week more than Xena. George earns $18 a week less than Xena. If Harry earns the same amount in two weeks that

George earns in three weeks, how much money does Xena earn a week?
This is Multi step equations and has to have a formula btw. Thanks. Help!!

Mathematics
1 answer:
saw5 [17]2 years ago
8 0

Answer:

Xena earns $144 a week

Step-by-step explanation:

Let,

Xena earns a week = X

Harry earns a week = (X + 45)

George earns a week = (X - 18)

According to the question,

2(X + 45) = 3(X - 18)

or, 2X + 90 = 3X - 54

or, 2X - 3X = -90 - 54

or, -X = - 144

or, X = 144 (Multiplying by -1 in both sides)

Therefore, Xena earns $144 a week.

Harry earns = $(144+45) = $189 and George earns $(144-18) = $126.

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The equation of the line f is y =4/9x+3/2.Line g is perpendicular to f. What is the slope of line g?
tangare [24]

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-9/4

Step-by-step explanation:

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7 0
2 years ago
A recipe for pie dough calls for a ratio of butter to flour of 1/4 :5/6.If you plan to use 5 cups of flour,how much butter shoul
Komok [63]

Answer:

\frac{3}{2}  cups of butter should be use to keep the same ratio.

Step-by-step explanation:

Given:

A recipe for pie dough calls for a ratio of butter to flour of 1/4 :5/6.

If you plan to use 5 cups of flour.

Now, to find the butter should be used to keep the same ratio.

So, to get the quantity of butter by using unitary method:

If, \frac{5}{6}  cup of flour use then butter should be = \frac{1}{4} .

So, 1 cup of flour use then butter should be = \frac{1}{4} \div \frac{5}{6} =  \frac{6}{20} .

Thus, for 5 cups of flour butter should be = \frac{6}{20} \times 5 = \frac{30}{20}=\frac{3}{2} .

Therefore, \frac{3}{2} cups of butter should be use to keep the same ratio.

5 0
3 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
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