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3 years ago

Circle O has a circumference of 367 cm

Mathematics

2 answers:

Advocard [28]3 years ago

8 0

For this case we have that by definition, the circumference of a circle is given by:

$C = \pi * 2r$

Where:

r: It is the radius of the circle

We have as data that:

$C = 367$

So: $367 = \pi * 2r$

We cleared the radio:

$r = \frac {367} {2 \pi}$

Taking $\pi = 3.14$ :

$r = \frac {367} {6.28}\\r = 58.44$

The length of the radio is 58.44cm

Answer:

58.44cm

Tanya [424]3 years ago

4 0

Answer:

18 cm

Step-by-step explanation:

Got it right edu

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What two numbers add to 8 and multiply to 28

anygoal [31]

Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x= $\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}$
x= $\frac{8+/- \sqrt{-48} }{2}$
x= $\frac{8+/- 4 \sqrt{-3} }{2}$
x= $4+/- 2 \sqrt{-3}$
x= $4+/- 2i \sqrt{3}$
there are no real numbers that satisfy this

5 0

3 years ago

HELP ASAP

joja [24]

Answer: The solutions are not viable because the amount of the sale cannot be negative.

Step-by-step explanation:

The solution A = -5 is not viable because A represents the amount of sale in dollars and so cannot be a negative number. The minimum amount that a person can make from sales is $0 so anything less than that is not viable.

For instance, if you are selling shoes for $4 each and make no sales in the day, your sales would be $0. It is not possible that your sales would be -$4.

6 0

2 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$