Answer:
v = 34.35 m/s
Explanation:
In order to find the speed of the car, when it has traveled 60m, you take into account the Work-Energy theorem, which is given by the following formula:
(1)
W: work done on the roller coaster by the electromagnetic propulsion
m. mass of the roller coaster = 700kg
v2: final speed of the roller coaster = ?
v1: initial speed = 0m/s
you have that the force exerted on the roller depends on x, the distance traveled by the roller. To calculate the work W, you use the following integral:
(2)
where F is given by:
You replace the previous function F in the integral (2) and calculate W:
Next, you solve the equation (1) for v2, and replace the values of all parameters:
The final speed of roller coaster, after it has traveled 60m is 34.35m/s
Ok so what we need to find is how large is the potential difference between points A and B.
Now you make a statement about what this potential difference would do in this problem
We now know that the points from A and B relies to transport a difference by using points A to B per unit change.
V
=
W/
q
=
50/
10
=
5
V=
q
W
=
10
50
=5 V (5 volt).
S=ut+a(t^2)/2 = a(t^2)/2 [since u=0] =(v/t)*(t^2)/2 [since a=(v-u)/t=v/t] =vt/2 =180*{25/(60*60)}/2 km = 0.625 km =625 m
It could measure the person's speed or also known as velocity. The object could be similar to a police officer using a radar gun to measure someone's MPH/speed.
From Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
<h3>
Newton's third law</h3>
This law states that action and reaction are equal and opposite. That is the force applied to an object is equal to the reaction received by the object.
F₁₂ = -F₂₁
m₁a₁ = -m₂a₂
m₁v₁/t = -m₂v₂/t
m₁v₁ = -m₂v₂
m₁v₁ + m₂v₂ = 0
<h3>For an elastic collision involving two objects</h3>
The sum of the initial momentum must be equal to sum of final momentum.
- let initial velocity = u
- let final velocity = v
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Thus, from Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
Learn more about conservation of linear momentum here: brainly.com/question/7538238