The answer would be B. It's really a circuit breaker but it works by comparing the amount of electrical current going to and returning from the item.
Answer:
The answer is 3,064x
Explanation:
When the collision happens, the momentum of the first car is applied to the both of them.
So we can calculate the force that acts on both cars as:
- The momentum of the first car is P = 2020 kg x 14.2 m/s = 28,684 kg.m/s
- The acceleration of both cars after the crash is going to be a = P / mtotal which will give us a = 28,684 / (2020+2940) = 5.78 m/s
- Since the second car was initially not moving, the final acceleration was calculated with the momentum of the first car.
Now we can find the force that acts on both of them by using the formula F = m.a which will give us the result as:
- F = (2020+2940) x 5.78 = 28,684
The friction force acts in the opposite direction and if they stop after moving 2.12 meters;
- Friction force is Ff = μ x N where μ is the friction coefficient and the N is the normal force which is (2020+2940) x 10 if we take gravitational force as 10, equals to 49,600.
- F - Ffriction = m x V
- 28,684 - μ x 49,600 = 4960 x 5.78
- μ = 3,064x

The African law ensures that people who are living with HIV/AIDS are not discriminated by the society by emphasizing that they must be protected by the law and enjoy the rights like those people in good conditions. It is in their Bill of Rights that people with HIV/AIDs are not forced to tell others about their status instead they have to enjoy their right to privacy and confidentiality.
Answer:
theoretically speaking I don't even wanna believe it's possible but if it does then then you should check for abortion
Answer:

Explanation:


If the sun considered as x=0 on the axis to put the center of the mass as a:

solve to r1


Now convert to coordinates centered on the center of mass. call the new coordinates x' and y' (we won't need y'). Now since in the sun centered coordinates the angular momentum was

where T = orbital period
then L'(x',y') = L(x) by conservation of angular momentum. So that means

Since
then
