Answer:
32
Step-by-step explanation:
We let the length of the square be l, the diagonal be z and the area be A.
Then by Pythagoras theorem;
The are of a square of length l is given as;
Combining these two equations yields;
Next, we have been given;
We are required to find;
when z = 4
By chain rule;
Differentiating with respect to z yields;
Therefore,
= 8z
When z is 4m the area of the square will be increasing at a rate of;
8m/min * 4m = 32
Answer:
ASA
Step-by-step explanation:
Given:
Two triangles ABC and EDC such that:
AB ⊥ BD and BD ⊥ DE
C is the midpoint of BD.
The two triangles are drawn below.
Since, AB ⊥ BD and BD ⊥ DE
Therefore, the two triangles are right angled triangle. The triangle ABC is right angled at vertex B. The triangle EDC is right angled at vertex D.
Since, point C is the midpoint of the line segment BD.
Therefore, C divides the line segment BD into two equal parts.
So, segment BC ≅ segment CD (Midpoint theorem)
Now, consider the triangles ABC and EDC.
Statements Reason
1. ∠ABC ≅ ∠CDE Right angles are congruent to each other
2. BC ≅ CD Midpoint theorem. C is midpoint of BD
3. ∠ACB ≅ ∠ECD Vertically opposite angles are congruent
Therefore, the two triangles are congruent by ASA postulate.
So, the second option is correct.
