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3 years ago

14

Solve y+x=-3 by graphing

2 answers:

Gnoma [55]3 years ago

7 0

Move x to the right side, so we could get y=-3-x.
If you didn't have a calculator, go to https://www.desmos.com/calculator and graph it. The rest is your work.

storchak [24]3 years ago

6 0

Y+x=-3
First, you move the x to the other side of the equals sign. so now it would be: y=-x-3. Now, you find one ordered pair. (0,-3). Now, you decrease the line by negative 1.
I can't expain it that well. I hope that helps.

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8y-2(y+4)= i was just wondering the best way to work this

Bond [772]

Answer:

6y-8

Step-by-step explanation:

8y-2(y+4)

8y-2y-8 distribution

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4 years ago

Sophia's teacher is talking to the class about net worth. What does it mean for someone to have positive net worth?

tiny-mole [99]

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8 0

3 years ago

6+n/5=9<br><br> What is happening to the variable? <br><br><br> How do you solve for the variable?

Svetradugi [14.3K]

Answer:

n=15

Step-by-step explanation:

(subtract 6 from both sides of the equation.)

6+n/5=9

6+n/5-6=9-6

(Now you will have to simplify.)

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(You will have to multiply all terms by the same value to eliminate fraction denominators.)

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And that's how you get your answer.

i hope this helps. :)

7 0

3 years ago

19 Select the decimal that is equivalent to 27 Choose 1 answer: А 0.626 B 0.626 C 0.703 0.703 E None of the above

Natali [406]

Answer:

I am pretty sure it is none of the above but I don’t know for sure

7 0

2 years ago

NEED The FULL equation. Will give Brainly. Thank you!

Ghella [55]

Answer:

$\displaystyle \sf h( - 1) = - \frac{ 2}{3}$

Step-by-step explanation:

we are given a function

$\displaystyle \sf h(x) = \frac{2x - 6}{4 {x}^{2} + 8}$

we would like to simplify it for h(-1)

in order to do so

substitute the value of x

$\displaystyle \sf h( - 1) = \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2} + 8}$

by order of PEMDAS

simplify square:

$\displaystyle \sf h( - 1) = \frac{2 \cdot - 1- 6}{4 { ( 1)}^{} + 8}$

simplify multiplication:

$\displaystyle \sf h( - 1) = \frac{ - 2 - 6}{4 { }^{} + 8}$

simplify addition:

$\displaystyle \sf h( - 1) = \frac{ - 2 - 6}{12}$

simplify subtraction:

$\displaystyle \sf h( - 1) = \frac{ - 8}{12}$

reduce fraction:

$\displaystyle \sf h( - 1) = - \frac{ 2}{3}$

5 0

3 years ago