small frames ($8): s
large frames ($15): L
Cost: 8s + 15L = 239 ⇒ 1(8s + 15L = 239) ⇒ 8s + 15L = 239
Quantity: s + L = 22 ⇒ -8( s + L = 22) ⇒ <u> -8s -8 L = -176 </u>
7L = 63
L = 9
Quantity: s + L = 22 ⇒ s + (9) = 22 ⇒ s = 13
Answer: 13 small frames, 9 Large frames
Answer:
x=
28
/89
Step-by-step explanation:
3x(32)=7x+28
Step 1: Simplify both sides of the equation.
96x=7x+28
Step 2: Subtract 7 from both sides.
96x 7x+28
−7 −7
89x=28
Step 3: Divide both sides by 89.
89x
/89
=
28
/89
It is definitely 36 i hope that this helps
Answer:
D
Step-by-step explanation:
Let the total production order be X. The combined rate is thus x/36 orders per hour.
Now, we know that the three machines are working at the same constant rate. This means that individual rate for each of the machines will be x/36 divided by 3 and that gives x/108 per machine.
Now, we are having another machine coming at the same constant rate. This means we are adding an x/108 rate to the preexisting x/36.
The new total rate thus becomes x/108 + x/36 = 4x/108
Now we know that the total new rate is 4x/108. Since the total work doesn’t change and it is still x, the time taken to complete a work of x orders at a rate of 4x/108 order per hour would be x divided by 4x/108 and this is x * 108/4x = 108/4 = 27 hours
Answer:
$3,000 was invested in the account that gained 13%
$17,500 was invested in the account that lost 10%
Step-by-step explanation:
Let the amount in both accounts be x and y
x for the first and y for the second
Adding both is 20,500
x + y = 20,500 •••••(i)
First account earned 13% profit
= 13/100 * x = 0.13x
Second account, a loss of 10%
= -10/100 * y = -0.1y
Total loss of -1,360
This is;
-0.1y + 0.13x = -1,360 •••••••(ii)
From i, x = 20,500-y
Insert this into ii
-0.1y + 0.13(20,500-y) = -1,360
-0.1y + 2665 -0.13y = -1360
-0.23y = -1360-2665
-0.23y = -4025
y = -4025/-0.23
y = 17,500
To get x, we have
x = 20,500 -y
x = 20,500- 17,500
x = 3,000
