<u><em>Answer:</em></u>
<u><em>Option A</em></u>
<u><em>Step-by-step explanation:</em></u>
<u><em>-(12 x 2) x (-6) = -12 x (2 x b)</em></u>
<u><em>=> -24 x -6 = -12 x 2b</em></u>
<u><em>=> 144 = -24b</em></u>
<u><em>=> b = -6</em></u>
<u><em>Hoped this helped.</em></u>
Answer: D (5/2, -17/4)
Step-by-step explanation: Using elimination your goal is to get rid or 1 variable so you can solve for the one that's left. By adding the -2y and 2y you will get 0. You will also add the 3x+x (4x) and -1+11 (10). You have now gotten rid of the y and have 4x=10. By dividing each side by 4 we now know x =2.5. D is the only possible solution with x=2.5 (5/2) but to solve for y you plug 2.5 in to an equation as x so) x-2y=11
2.5-2y=11
-2y=8.5 Answer D (5/2,-17/4) y=-17/4 (4.25)
Answer:
<h2>4/3 Joules </h2>
Step-by-step explanation:
Work is said to be done when force applied to an object causes the object to move through a distance.
Work done = Force * perpendicular distance.

Given Force F = xy i + (y-x) j and a straight line (-1, -2) to (1, 2)
First we need to get the equation of the straight line given.
Given the slope intercept form y = mx+c
m is the slope
c is the intercept
m = y₂-y₁/x₂-x₁
m = 2-(-2)/1-(-1)
m = 4/2
m = 2
To get the slope we will substtutte any f the point and the slope into the formula y = mx+c
Using the point (1,2)
2 = 2+c
c = 0
y = 2x
Substituting y = 2x into the value of the force F = xy i + (y-x) j we will have;
F = x(2x) i + (2x - x) j
Using the coordinate (1, 2) as the value of s
![W = \int\limits^a_b ({2x^2 i + x j}) \, (i+2j)\\W = \int\limits^a_b ({2x^{2}+2x }) \, dx \\W = [\frac{2x^{3} }{3} +x^{2} ]\left \ x_2=1} \atop {x_1=-1}} \right.\\W = (2(1)^3/3 + 1^2) - (2(-1)^3/3 + (-1)^2)\\W =(2/3+1) - (-2/3+1)\\W = 2/3+2/3+1-1\\W = 4/3 Joules](https://tex.z-dn.net/?f=W%20%3D%20%5Cint%5Climits%5Ea_b%20%28%7B2x%5E2%20i%20%2B%20x%20j%7D%29%20%5C%2C%20%28i%2B2j%29%5C%5CW%20%3D%20%5Cint%5Climits%5Ea_b%20%28%7B2x%5E%7B2%7D%2B2x%20%7D%29%20%5C%2C%20dx%20%5C%5CW%20%3D%20%5B%5Cfrac%7B2x%5E%7B3%7D%20%7D%7B3%7D%20%2Bx%5E%7B2%7D%20%5D%5Cleft%20%5C%20x_2%3D1%7D%20%5Catop%20%7Bx_1%3D-1%7D%7D%20%5Cright.%5C%5CW%20%3D%20%282%281%29%5E3%2F3%20%2B%201%5E2%29%20-%20%20%282%28-1%29%5E3%2F3%20%2B%20%28-1%29%5E2%29%5C%5CW%20%3D%282%2F3%2B1%29%20-%20%28-2%2F3%2B1%29%5C%5CW%20%3D%202%2F3%2B2%2F3%2B1-1%5C%5CW%20%3D%204%2F3%20Joules)
Answer:
B) {-8, -3, 5, 7}
Step-by-step explanation:
Range is a list of y values
= {-8, -3, 5, 7}
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