How to solve this problem by classifying systems of equations 3x+4y=36 -5x=35-3y
1 answer:
Answer:
x=-32/29
Step-by-step explanation:
3x+4y=36 Equation 1
-5x+3y=35 Equation 2
Multiplying equation 1 with 3 (value before y in equation 2) and equation 2 with 4 (value before y in equation 1) we obtain equations 3 and 4 as follows
9x+12=108 equation 3
-20x+12y=140 equation 4
Subtracting equation 3 from equation 4 we obtain
-29x=32
x=-32/29
To find the value of y, we substitute the value of x into equation 2 as initially given in the equation
-5(-32/29)=35-3y
-5(-32/29)-35=-3y
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To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides
1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself