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Shalnov [3]
3 years ago
5

How to solve this problem by classifying systems of equations 3x+4y=36 -5x=35-3y

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer:

x=-32/29

y=9\frac {24}{29}

Step-by-step explanation:

3x+4y=36 Equation 1

-5x+3y=35 Equation 2

Multiplying equation 1 with 3 (value before y in equation 2) and equation 2 with 4 (value before y in equation 1) we obtain equations 3 and 4 as follows

9x+12=108 equation 3

-20x+12y=140 equation 4

Subtracting equation 3 from equation 4 we obtain

-29x=32

x=-32/29

To find the value of y, we substitute the value of x into equation 2 as initially given in the equation

-5(-32/29)=35-3y

-5(-32/29)-35=-3y

y=9\frac {24}{29}

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