Let:
x = hours of travel
y = velocity
slope= rise/run slope=(y2-y1)/(x2-x1)
(x1,y1) = (2,50) (x2,y2) = (6,54)
sub values back into the equation m = (54-50)/(6-2) m = 1
POINT SLOPE FORMy-y1 = m(x-x1) y-50= 1(x-2) y = x -2 +50
y = x + 48
B)
the graph within the first seven hours can be obtained at point B
x = 7
y = 7+48 = 55
B(7,55)
Answer:
10/3
Step-by-step explanation:
31/8= 3.8
10/3= 3.3
Answer:
8.5
Step-by-step explanation:
Answer: D) 300 degrees (counterclockwise)
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We want to have segment PQ rotate around the center so that it lines up with segment RF. Put another way: we want point P to rotate around the center to have it line up with point R, and we want Q to rotate so that it moves to point F.
Going clockwise, this is a rotation of 60 degrees as the diagram below shows (each blue arc is 30 degrees, so in total it's 30+30 = 60). In that diagram, I'm only focusing on moving point P. Point Q moves in a similar fashion. Since 60 is not an answer, this means 360-60 = 300 must be the answer.