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tatiyna
3 years ago
9

What are all of the factors of 27?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0
1, 3, 9, 27

1 * 27 = 27

3 * 9 = 27

^those are all the factors.
hope this helps :)


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Hugh says that “one less than four times a number” can be written as two expressions: 1 - 4n and 4n - 1. Why is Hugh incorrect?
Basile [38]

Answer:

N times 4-1

Step-by-step explanation:

4 times number is not a squared number where you multiply- the number

by it's self and then you subtract 1

8 0
3 years ago
The scatterplot shows the data collected from a survey of 19 students, in which they were asked how many hours per week they stu
konstantin123 [22]

Answer:

The Answer is B) There is a positive correlation between them.

Step-by-step explanation:

There is a positive correlation between them. Since the points on the graph tend to rise from left to right, the correlation is positive.

3 0
3 years ago
Read 2 more answers
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
1 year ago
1. 8x-x <br> solve <br> I NEED HELPPP ASAP
White raven [17]

Answer:

<h2>7x</h2>

Step-by-step explanation:

8x-x\\\mathrm{Add\:similar\:elements:}\:8x-x=7x

4 0
3 years ago
Read 2 more answers
What is the value of n?<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2n-7%7D%7B3%7D%20%3D15" id="TexFormula1" title=" \fra
kirill [66]
\frac{2n-7}{3} = 15

2n - 7 × 1 = 15 × 3

2n - 7 = 45

2n = 45 + 7

2n = 52

n = 26

Have a nice days.........
5 0
3 years ago
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