i love these types of problems! i'm going to use my name, cherry, if that's ok.
cherry had 10 buttons in her collection. cherry made a deal with a friend that allowed her to receive 5 new buttons per week. after a certain number of weeks, cherry had acquired a total of 50 buttons! how many weeks had cherry's friend given her buttons?
- cherry :)
Answer:
x =-3
Step-by-step explanation:
A hole of a simplified rarional funcrion as the one given above exists when there is a number that can make both the numerator & the denominator = 0
so plug -3 in the x of the function & you'll get 0/0 which is indeterminate & thus implies the existence of a hole
F(x) = x² - 13x + 30
f(x) = x² - 3x - 10x + 30 = 0
f(x) = x(x - 3) -10(x - 3) = 0
f(x) = (x-3)(x-10) = 0
f(x) = 3 OR 10
In short, Your Answer would be Option B & D
Hope this helps!
Answer:
cot B = 48/55
Step-by-step explanation:
cot B = 48/55
