Answer:
Step-by-step explanation:
Given that
To find tangent, normal and binormal vectors at (0,0,1)
i) Tangent vector
At the particular point, r'(t) = (1,1,e)
Tangent vector = 
ii) Normal vector
T'(t) = 
At that point T'(t) = (0,0,e)/e = (0,0,1)
iii) Binormal
B(t) = TX N
= ![\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%26e%5Et%5C%5C0%260%26e%5Et%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%3D%20e%5Et%28i-j%29)
Do the opposite of what you did in reverse order.
so add 100 and divide by 2 in that order.
(80 + 100)/2
Hey there!
<u>Opposite sides are congruent:</u>
all of them
<u>opposite angles are congruent</u>
rectangle and square
<u>all sides are congruent</u>
rhombus and square
<u>diagonals congruent:</u>
rectangle, rhombus, and square
<u>diagonals are perpendicular</u>
square and rhombus
Have a terrificly amazing day!
Answer:
3/4
Step-by-step explanation:
Choose two coordinates on the line and use the slope formula to figure out the slope.
For example, use coordinates (0,-1) and (4,2).
Slope formula: y2-y1/x2-x1
2--1/4-0 = 3/4
