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sattari [20]
2 years ago
8

What is the product of 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°))

Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is 520[cos(18) + isin(18)]

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Complex number is in the form z = a + bi, where a and b are real numbers.

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is:

z = 65 * 8 [cos(14 + 4) + isin(14 + 4)] = 520[cos(18) + isin(18)]

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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