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sattari [20]
2 years ago
8

What is the product of 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°))

Mathematics
1 answer:
saveliy_v [14]2 years ago
3 0

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is 520[cos(18) + isin(18)]

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Complex number is in the form z = a + bi, where a and b are real numbers.

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is:

z = 65 * 8 [cos(14 + 4) + isin(14 + 4)] = 520[cos(18) + isin(18)]

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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University Theater sold 556 tickets for a play. Tickets cost $22 per adultand $12 per senior citizen. If total receipts were $84
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To find the answer, set up a system of equations.

Let x=adult tickets and y=senior citizen tickets.

x+y=556
22x+12y=8492

Change the first equation to make it easy to combine with the second equation.

y=556-x

Now substitute (556-x) for y in the second equation.

22x+12(556-x)=8492

Simplify and combine like terms.

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x=182

182 adult tickets were sold, so to solve for the number of senior citizen tickets sold, subtract 182 from 556.

556-182=374

374 senior citizen tickets were sold.
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2³ · 11

Step-by-step explanation:

                                                             88

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Prime factorization: 2³ · 11

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