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3 years ago

Find x!!! pls fast !! see photo for question

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

I believe that the answer would be 45

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Margo borrows $2000, agreeing to pay it back with 7% annual interest after 17 months. How much interest

julia-pushkina [17]

Answer:

1000

Step-by-step explanation:

bc i dont know thats why hope it helped

7 0

2 years ago

In each box, 15% of the total candies are cherry flavored. In a box of 20 candies, how many are cherry flavored? Enter the missi

Yanka [14]

The answer is 3. I don't know if you want ne to explain or show my work just reply to me.

5 0

3 years ago

Read 2 more answers

suppose you deposit $1000 in a savings account that pays 4.8% interest compounded monthly. Write an exponential function to mode

zubka84 [21]

Answer:

The exponential function is $A(t) = 1000(1.004)^{12t}$ .

You will have $1,100.55 in the account after 2 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Deposit $1000 in a savings account that pays 4.8% interest compounded monthly.

This means that $P = 1000, r = 0.048, n = 12$ . So

$A(t) = P(1 + \frac{r}{n})^{nt}$

$A(t) = 1000(1 + \frac{0.048}{12})^{12t}$

$A(t) = 1000(1 + 0.004)^{12t}$

$A(t) = 1000(1.004)^{12t}$

This is the exponential function

How much will you have in your account after 2 years?

This is A(2). So

$A(2) = 1000(1.004)^{24} = 1100.55$

You will have $1,100.55 in the account after 2 years.

5 0

2 years ago

A teacher gives a test with questions that fall into 3 levels of difficulty (easy, moderate, and hard).

Tpy6a [65]

When a teacher gives a test with questions that fall into 3 levels of difficulty (easy, moderate, and hard) The scoring method that would best allow her to identify the students who need help is:
B. weight each question by its difficulty: 1 for easy, 2 for moderate, and 3 for hard.

4 0

3 years ago

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0

3 years ago