This can be solved with Punnett squares. The affected male has the
genotype, and the female is homozygous recessive. This means that she does not carry this, and therefore, will have the genotype XᵇXᵇ
While doing this Punnett Square, keep in mind that in order to have the male offspring affected, their genotype
has to be
Since there are no
, the probability of their male offspring inheriting this disease is 0%
For this you are going to use S as the dominate and r for the recessive. Since both of the parents are squared eye the offspring's likely chance of having round eyes will be 0%.
I believe it would be proteins
This is happen during anaphase when two chromatids separate and move towards opposite poles,