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gulaghasi [49]
3 years ago
14

Annual returns on stock of the Mean Corporation are approximately normally distributed with a mean of 13.9% and standard deviati

on of 4.9%. Joe Prudent is considering investing in the Mean Corporation. According to his investment strategy, he will only invest if the chance of an annual return of 11% or more is greater than 70%. In answering the following question, a)Calculate the corresponding standardized value (z) for an annual return of 11%. Give your answer to 2 decimal places. z = b)Therefore, according to his investment strategy, Joe: will invest in Mean Corporation will not invest in Mean Corporation is indifferent to investing in Mean Corporation
Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

(a) z=-0.59

(b) Joe will invest in Mean Corporation. The probability of getting an annual return grater than 11% is 72.3%.

Step-by-step explanation:

We have a normal distribution for the annual return of the stock.

This distribution has mean of 13.9% and s.d. of 4.9%.

If X=11%, we can calculate its corresponding z-value as:

z=\frac{X-\mu}{\sigma}= \frac{0.11-0.139}{0.049}= -0.5918

The z-value is z=-0.5918.

The probabilty of P(X>11%)=P(y>-0.5918) is, by the standarized normal distribution table, equal to 0.723.

As its P(y>-0.5918)=P(X>11%)=0.723 bigger than the 70% threshold, Joe will invest in Mean Corporation.

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3 years ago
So desperate giving all of my points for this. Please show work and I'll give Brainliest. Please god please god please god
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4 0
2 years ago
Team A and Team B are competing against each other in a game of tug-of-war. Team A, consisting of 3 males and 3 females, decides
saul85 [17]

Answer:  Team A will choose one of 36 possible lineups.

Step-by-step explanation:  Given that Team A and Team B are playing the game of tug-of-war.

Team A has 3 males and 3 females that decides to line up  male, female, male, female, male, female.

We are to find the number of possible lineups that Team A can make.

According to the given information,

number of options for the first position = 3,

number of options for the second position = 3,

number of options for the third position = 2,

number of options for the fourth position = 2,

number of options for the fifth position = 1

and

number of options for the sixth position = 1.

Therefore, the number of possible lineups by Team A is

n=3\times3\times2\times2\times1\times1=36.

Thus, Team A will choose one of 36 possible lineups.

4 0
3 years ago
A jar contains 2 green marbles, 4 blue marbles, and 3 yellow marbles. A marble is chosen at random from the jar and replaced. Fi
omeli [17]

Answer:

2/27

Explanation:

• Number of green marbles = 2

,

• Number of blue marbles = 4

,

• Number of yellow marbles = 3

Total = 2+4+3 =9

• Probability of choosing a green marble = 2/9

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• Probability of choosing a yellow marble = 3/9

Therefore, the possibility that the first marble is green and the second is yellow is:

\begin{gathered} =\frac{2}{9}\times\frac{3}{9} \\ =\frac{2}{27} \end{gathered}

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1 year ago
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50 km/h = 4 hours
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50x = 60×4

50x = 240

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3 years ago
Read 2 more answers
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