Answer:
z=80°<em><u>(</u></em><em><u>corresponding</u></em><em><u> </u></em><em><u>angles)</u></em>
<em><u>
</u></em>
<em><u>y=</u></em><em><u>100 </u></em><em><u>° </u></em><em><u>(</u></em><em><u>alternate</u></em><em><u> </u></em><em><u>angles</u></em><em><u>)</u></em>
<h2>
<em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>
Hello!
As you can see, 22 is the opposite angle. We are looking for the adjacent angle. Let's just call it x. Using SOH CAH TOA, we see that the tangent is the opposite divided by the adjacent side. Let's use that.
tan54≈1.38
This gives us the equation below.
1.38=22/x
Let's solve this equation for x.
1.38x=22
x=22/1.38
x=15.94
Therefore, the length of the shadow is about 15.94 meters.
I hope this helps!
Answer:
picture is too small .i am not able to see
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
