In order to determine the vertex of this, you can complete the square. To do that, first set the equation equal to 0, then move the -35 over to the other side by adding. That gives us

. Now we can complete the square. Do this by taking half of the linear term, squaring it, and adding it in to both sides. Our linear term is 2x. Half of 2 is 1, and 1 squared is 1. So we add 1 to both sides, creating something that looks like this:

. We will do the math on the right and get 36, and the left will be expressed as the perfect square binomial we created by doing this whole process.

. Now move the 36 over by subtraction and set it back to equal y and your vertex is apparent. It is (1, -36). You find the x-intercepts when y = 0. That means you need to set your original equation equal to zero and factor it. The easiest, surest way to do this is to use the quadratic formula. Doing that gives us x values of 7 and -5. And you're done!
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Explanation:</h2><h2>
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The diagram is missing but I'll assume that the arc BDC is:

And another arc, let's call it FGH. measures:

If those arc are equal, then this equation is true:

Substituting k into the first equation:

Answer:
length: 200
width: 65
Step-by-step explanation:
length: 3w + 5
width: w
perimeter = 2L + 2W
530 = 2(3w + 5) + 2w
530 = 6w + 10 + 2w
530 = 8w + 10
520 = 8w
w = 65
length: 3w + 5 = 3(65) + 5 = 200
width: w = 65
3n=27+3
you can do anything as long as you do it to both sides
3n=27+3
add like terms
27+3=30
3n=30
divide both sides by 3
n=10
Answer: 11:47
Step-by-step explanation: