How many groups were there
Answer:
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
Step-by-step explanation:
Given the simultaneous equation
2x- 6y=6 ... 1
6x - 4y = 2 ... 2
To eliminate a variable, we have to make the coefficient of one of the variable to be the same.
Multiply equastion 1 by -3
-6x+18y= -18
6x - 4y = 2
Add the result:
-6x + 6x + 18y-4y = -18+2
18y-4y = -18+2
14y = -18
y = -9/7
Another way is to Multiply the bottom equation by -3/2 then add the equations.
Multiplying equation 2 by -3/2 will give;
6x(-3/2) - 4y(-3/2) = 2(-3/2)
-9x + 6y = -3
Add to equation 1;
2x- 6y=6
-9x + 2x + 0 = -3+6
-7x = 3
x = -3/7
Hence the correct two options are;
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
<em></em>
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Answer:
Step-by-step explanation:
really need these points im sorry good luck tho
AC side and BC side have the same length because ΔCDA and ΔCDE are congruent.
The equation will be
AC = BC
Solve the equation
AC = BC
2x = 3x - 10
2x - 3x = -10
-x = -10
x = 10
The value of x is 10
