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3 years ago

At the movie theatre, child admission is $5.10 and adult admission is $9.00 .

Mathematics

1 answer:

sveticcg [70]3 years ago

8 0

Answer:

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue for Wednesday was 831.60. So then we can set up the following equation for the total revenue

$5.10 X +9.00 Y = 831.60$

We also know that for Wedneday we have two times tickets for adults compared to child so we have

$Y =2x$

And using this condition we have:

$5.10 X + 18 X = 831.60$

And solving for X we got:

$X= \frac{831.60}{23.1}=36$

So then the number of tickets sold for child are 36

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Answer:

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Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

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Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

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