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ivann1987 [24]
3 years ago
12

(5x - 2y = 22 8x - 2y = 28 Please!! Urgent

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0

9514 1404 393

Answer:

  (x, y) = (2, -6)

Step-by-step explanation:

Subtract the first equation from the second.

  (8x -2y) -(5x -2y) = (28) -(22)

  3x = 6

  x = 2

Substitute this into either equation and solve for y.

  8(2) -2y = 28

  8 -y = 14 . . . . . . . . divide by 2

  y = 8 -14 = -6 . . . . add y-14 to both sides

The solution is (x, y) = (2, -6).

_____

I like a graphing calculator for a quick solution to such problems.

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A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment i
Tasya [4]

Answer:

(3,7) for the first line, and (12,0) for the second one.

Step-by-step explanation:

Hi Isabella,

1) The Midpoint of a line, when it comes to Analytical Geometry, is calculated as Mean of two points it follows:

x_{m}=\frac{x_{1} +x_{2} } {2}, y_{m} =\frac{y_{1}+ y_{2} }{2}

2) Each segment has two endpoints, and their midpoints, namely:

a) (1,-9) and its midpoint (2,-1)

b) (-2,18) and its midpoint (5,9)

3) Calculating. You need to be careful to not sum the wrong coordinates.

So be attentive!

The first line a

2=\frac{1+x_{2} }{2}\\  4=1+x_{2}\\  4-1=-1+1+x_{2} \\ x_{2}=3\\-1=\frac{y_{2}-9}{2}\\-2=y_{2}-9\\+2-2=y_{2}-9+2\\ y_{2}=-7

So (3,7) is the other endpoint whose segment starts at (1,-9)

The second line b endpoint at (-2,18) and its midpoint (5,9)

5=\frac{-2+x_{2} }{2} \\ 10=-2+x_{2} \\ +2+10=+2-2+x_{2}\\ x_{2}=12 \\ \\ 9=\frac{18+y_{2} }{2} \\ 18=18+y_{2} \\ -18+18=-18+18+y_{2}\\ y_{2} =0

So (12,0) it is the other endpoint.

Take a look at the graph below:

8 0
3 years ago
What is (f ° g)(2) and (g ° f)(2) with the set of points f: {(0,4), (1,2), (2,0), (3,2), (4,4)} and g: {(0,4), (1,3), (2,2), (3,
kumpel [21]

Answer:

\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}

Step-by-step explanation:

f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/

7 0
3 years ago
Y = 2x + 3
BARSIC [14]

Answer:

Infinite solution

Step-by-step explanation:

There is 3 possible solutions to a system of linear equations:

  • One solution - two distinct lines that do not share y-intercept or slop intersect at a point
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  • Infinite solution - one distinct function represented two ways which in simplest form share the same slope and y-intercept

The first equation is in simplest form y=2x+3.

The second equation 2y=4x+6 when simplified becomes y=2x+3.

These are the same lines with the same slope and y-intercept. Therefore, they have infinite solutions.


3 0
3 years ago
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