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givi [52]
3 years ago
13

Can anybody answer this correctly thank you

Mathematics
1 answer:
Ghella [55]3 years ago
4 0

its the second one....

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5x-2y=11 and 3x+4y=4<br>Find the value of x and y in equation.​
nadya68 [22]
  • 5x-3y=11---(1)
  • 3x+4y=4---(2)

(1)×3 and (2)×5

  • 15x-9y=33-(3)
  • 15x+20y=20-(4)

Subtract both

\\ \sf\longmapsto -29y=13

\\ \sf\longmapsto y=\dfrac{-13}{29}

  • Put in eq(1)

\\ \sf\longmapsto 5x+\dfrac{-117}{29}=11

\\ \sf\longmapsto 5x=11+\dfrac{117}{29}=\dfrac{261+117}{29}=\dfrac{278}{29}

\\ \sf\longmapsto x=\dfrac{278}{145}

7 0
2 years ago
Read 2 more answers
What is the answer to 3x + 2 = 4x
Sedbober [7]
X=2
because if you subtract 3x on both sides you end up with x=2 <span />
5 0
3 years ago
What is 3/7 as decimal
maksim [4K]

Answer:

0.428571429

Step-by-step explanation:

4 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
Brian compared the absolute values of the numbers−12,34,and−14.Arrange the numbers from least to greatest.
solniwko [45]

Answer:

-12, -14, 34

Step-by-step explanation:

3 0
3 years ago
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