Question

Find the 96th term of the arithmetic sequence -16,-28,-40 (im stuck on this please help)

Answer 1

Answer:

1124.

Step-by-step explanation:

The common difference (d)   is -16 - (-28) = 12,  ( also -28 - (-40) = 12).

The nth term of an A.S.  is a1 + d(n - 1)  where a1 = first term, d=common difference.

so the 96th term of the given A.S. is:

-16 + 12(96 - 1)

= -16 + 12*95

= 1124.

hope this help