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Lemur [1.5K]
3 years ago
7

Plz help me hurry plz Direct variation

Mathematics
1 answer:
Furkat [3]3 years ago
7 0

Answer:

sorry I need some point

Step-by-step explanation:

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On a given line, (on one side) there are a total of 180°

if one line in Problem #3 is bisected by a line, with one half X and the other 120°,

do 180° (the total) minus 120° which=60°

now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6

this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
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7 0
2 years ago
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
3 years ago
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