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Lubov Fominskaja [6]
4 years ago
8

Does anyone know this?

Mathematics
1 answer:
Bond [772]4 years ago
8 0

Step-by-step explanation:

measure \: of \: interior \: angle \\  =  \frac{ (18 - 2) \times 180 \degree}{18}  \\  = 16 \times 10 \degree \\  = 160 \degree \\  \\ measure \: of \: exterior \: angle \\  =  \frac{360 \degree}{18}  = 20 \degree \\  \\  \\

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MEDALS REWARDED!. . Find the exact value of (cos-1) square root of two divided by two.
HACTEHA [7]

The exact value of the given equation is 45 degrees or pi/4. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

4 0
3 years ago
Two friends start at the same point. they walk in opposite directions for 3 meters, then turn left and walk another 3 meters. th
vladimir2022 [97]
3^2+3^2=18
√ 18 + √18=2√18 or 6√2 meters
They are 6√2 meters apart or approximately 8.49 meters.
3 0
3 years ago
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0
3 years ago
I do not get this anyone know???
Allushta [10]
Look at the picture.
O=12\\A=5\\H=13\\\\\sin B=\dfrac{12}{13}\\\\\cos B=\dfrac{5}{13}\\\\\tan B=\dfrac{12}{5}

8 0
3 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
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