Question

1. Find the equation of a line passing through the points (1,-2) and (-3,10).​

Answer 1

Answer:

Step-by-step explanation:

(1 , -2)   x₁ =1 & y₁ = -2

(-3,10)  x₂= -3 & y₂ = 10

First we need to find the slope.

$\boxed{Slope = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}} }$$\boxed{Slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}}$

          $=\dfrac{10-[-2]}{-3-1}\\\\\\=\dfrac{10+2}{-4}\\\\\\=\dfrac{12}{-4}\\\\\\= - 3$

m = -3

Equation of the line: y = mx + b

y = -3x + b

To find the value of b, take one of the point and substitue in the above equaiton.

(1 , -2)

-2 = -3*1 + b

-2 = -3 + b

-2 + 3 = b

b = 1

Equation of the line:

y = -3x + 1