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Tanya [424]
4 years ago
8

For x > 3, values of the function f(x) = –(x – 3)^2(x + 2) are negative. On this same interval, which statement correctly des

cribes the values of the additive and multiplicative inverses?
A) Both the additive inverse and the multiplicative inverse are positive.
B) Both the additive inverse and the multiplicative inverse are negative.
C) The additive inverse is positive, while the multiplicative inverse is negative.
D) The additive inverse is negative, while the multiplicative inverse is positive.
Mathematics
2 answers:
kumpel [21]4 years ago
5 0

Answer:

C) The additive inverse is positive, while the multiplicative inverse is negative.

Step-by-step explanation:

The answer is C on Edge.   (VERIFIED Edge Answer)

Make sure to click "thanks" and rate this answer to let others know this is the correct answer for this question.  

Edge Tip: Answers do not mix or change.

Leokris [45]4 years ago
4 0
The addictive inverse is positive while the multiplicative inverse is negative
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Given: △ABC is equilateral, △ADC is isosceles,
KonstantinChe [14]

Answer:


Step-by-step explanation:

Since ABC is an equilateral triangle, thus AB=BC=AC=x, therefore

The perimeter of ΔABC=36

⇒AB+BC+AC=36

⇒x+x+x=36

⇒3x=36

⇒x=12

Thus, AB=BC=AC=12.

Now, Since ΔADC is isosceles triangle, therefore AD=DC=y.

Perimeter of ΔADC=40

⇒AD+DC+CA=40

⇒x+y+y=40

⇒12+2y=40

⇒2y=28

⇒y=14

Therefore, AD=DC=14

Thus, Length of sides of ΔABC are AB=BC=AC=12 and Length of sides of ΔADC are AD=DC=14.

7 0
3 years ago
after paying t toward her tuition, julie still owed 35% of her total tuition of $850.00, leaving an amount due of $339.50
Nataly_w [17]

Um I don;t see the question here...

3 0
4 years ago
What are some easy ways to find the value of<br> (2017^4−2016^4)/(2017^2+2016^2) without calculator
scoray [572]

Answer:

4033

Step-by-step explanation:

An easy way to solve this problem is to notice the numerator, 2017^4-2016^4 resembles the special product a^2 - b^2. In this case, 2017^4 is a^2 and 2016^4 is b^2. We can set up equations to solve for a and b:

a^2 = 2017^4

a = 2017^2

b^2 = 2016^4

b = 2016^2

Now, the special product a^2 - b^2 factors to (a + b)(a - b), so we can substitute that for the numerator:

<h3>\frac{(2017^2+2016^2)(2017^2 - 2016^2)}{2017^2+2016^2}</h3>

We can notice that both the numerator and denominator contain 2017^2 + 2016^2, so we can divide by \frac{2017^2+2016^2}{2017^2+2016^2} which is just one, and will simplify the fraction to just:

2017^2 - 2016^2

This again is just the special product a^2 - b^2, but in this case a is 2017 and b is 2016. Using this we can factor it:

(2017 + 2016)(2017 - 2016)

And, without using a calculator, this is easy to simplify:

(4033)(1)

4033

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3 years ago
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rodikova [14]
For the first option, since when x is going down (to the left) the function is going up, it's not approaching 0. For the second option, since when x is going up (to the right) it's going up, it's not approaching negative infinity (negative infinity is all the way down). For the third one, since when x is going down the y values are climbing, we can assume that the function's values go to positive infinity. For the last one, since when x=0 y=0, when x=0 the function does not go to infinity
8 0
4 years ago
2y+3x=90 what is x and y
yan [13]

If x=-6 then y=54.
If x=-4 then y=51.
If x=-2 then y=48.
If x=0 then y=45.
If x=2 then y=42.
If x=4 then y=39.
If x=6 then y=36.

There are an infinite variety of pairs of numbers for 'x' and 'y'
that can make that equation true.

You can use that equation to draw a  line on a graph.  Then
EVERY point on the line is a solution to the equation.

'x' and 'y' don't have single values unless you have TWO equations.

4 0
3 years ago
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