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3 years ago

1/4y + 1 1/2 + 2 − 1 3/4y − 12 = ?

Mathematics

2 answers:

pantera1 [17]3 years ago

8 0

Brung like terms together:-
1/4 y - 1 3/4 y + 11/2 + 2 - 12
= - 1 1/2 y + 11/2 - 10
= - 1 1/2y - 9/2

bija089 [108]3 years ago

4 0

HOPE THIS HELP MAH DUDE

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1.Consider the system of equations. x-5y=2

JulijaS [17]

1.Consider the system of equations. x-5y=2
3x-10y=11

(a) Jamar rewrote the first equation as –2x + 10y = –4. What justification did he have for doing this?

(b)Jamar combined the equation in Part (a) with the second equation in the system to get x = 7. Explain Jamar’s reasoning.

(c) What is the solution of the system? (d) How do you know, without graphing, that the graph of 4x – 15y = 13 passes through the point whose coordinates are the solution of the system?

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2 years ago

The city of Yorkton, Saskatchewan, has an area of 24.0 km^2. If this city were a perfect square, what would it’s exact perimeter

Elis [28]

Answer:

8 $\sqrt{6}$ inches

Step-by-step explanation:

Let l represent the length of the square

The area of a square = l^2

That means,

l^2 = 24 km^2

Take the square root of both sides

l = $\sqrt{24}$

l = $\sqrt{4*6$

l = $\sqrt{4} *\sqrt{6}$

l = 2 $\sqrt{6}$

Now lets find the perimeter

Perimeter of a square, P = 4l

P = 4* 2 $\sqrt{6}$

P = 8 $\sqrt{6}$ inches

3 0

3 years ago

What times what =13?

patriot [66]

Answer:

1x13 :-)

1 x 13 = 13

8 0

3 years ago

Read 2 more answers

WHOEVER EXPLAINS ALL THEIR WORK AND GOES THROW EAXH STEP WILL GET BRAINLEST THAT IS COMPLETELY FINISEHD. write the equation of t

neonofarm [45]

Answer:

$y = -3x+11$

Step-by-step explanation:

I accept your challenge!

First we know that a equation of the line is a linear equation, and its equation is:

$y = mx+b$

$m: \text{slope}\\b: \text{y-intercept}$

In this context, the slope, defined as the steepness of a line is characterized as the ratio of RISE (the difference in the y-coordinates, the vertical change) over the RUN (the difference in x-coordinates, the horizontal change).

$m=\frac{\text{change in y}}{\text{change in x}}=\frac{\Delta y}{\Delta x}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$