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Pani-rosa [81]
3 years ago
5

How can you use substitution method to solve a system of equations that does not have a variable with a coefficient of 1 or –1?

Mathematics
1 answer:
kap26 [50]3 years ago
6 0
You can multiply or divide one equation so that it has a variable with a coefficient opposite of the other equation.
Example:
A) 2x + 3y = 6
B) 4x +2y = 20
Notice that neither equation has a "1" or "-1"
Let's multiply Equation A) by -2
A) -4x -6y = -12 Then add it to B)
B) 4x +2y = 20
-4y = 8
y= -2

A) 2x + 3*-2 = 6
2x = 12
x = 6



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A real estate sales agent receives a salary of $250 per week plus a commission of 2% of sales. Write an
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3 0
3 years ago
Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $3,169 was collected on the sale of 1,325 ticket
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Answer:

461 adults and 864 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 1,325 tickets were purchased, then s+a=1325.

We also know that a total of $3,169 was collected and adult tickets cost $5 each and students cost $1 each. We can write 1s+5a=3169.

We will solve by substituting one equation into the other. We first solve the first equation for s which is s=1325-a. Substitute s=1325-a into 1s+5a=3169. Simplify and isolate the variable a.

1(1325-a)+5a=3169

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This means that 461 adults attended and 864 students attended since 864+461=1325.

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