Answer:
The total cost of 1 belt and 1 tie is $13 and $39 respectively.
Step-by-step explanation:
Given that,
The cost of 4 belts and 5 ties is $247.
Each tie costs 3 times as much as a belt.
Let the cost of a belt is x and that of a tie is y.
ATQ,
4x + 5y = 247 ...(1)
y = 3x ....(2)
Put the value of y from equation (2) in equation (1)
4x + 5(3x) = 247
4x + 15x = 247
19x = 247
x = 13
Put the value in equation (2)
y = 3x
= 3(13)
= 39
So, the total cost of 1 belt and 1 tie is $13 and $39 respectively.
You would need to multiply 35 x .6 (which is 60%).
35 x .6 = 21, so at least 21 members need to be present to vote.
Answer:
Step-by-step explanation:
If all had been children's tickets, revenue would have been $925. Actual revenue is $1150 -925 = $225 more than that. Changing a child's ticket to an adult's ticket add $1 to the revenue, so there must be $225 such changes.
The number of adult tickets is 225; the number of children's tickets is 925-225 = 700.
Answer: z = -19.5
Step-by-step explanation:
-6.5 = z/3
-19.5 = z Multiply 3 to both sides
Answer:
Step-by-step explanation:
Remark
The two black suites are
Clubs
Spades
Each of them has 13 cards so the total number of black cards is 2*13 = 26
Add to that the hearts which also has 13 cards
The total number of possible good cards is 13 + 26 = 39
Answer
P(hearts or Black) = 39/52
P(hearts or Black) = 3/4
P(hearts or Black) = 0.75
