N=1,
a1= 48-1*11=48-11=37
a2= 48 -2*11=48 -22=26
d= 26 -37 = -11
a(n) = a(n-1) - 11
a1=37
a(n) = a(n-1) - 11
Check:
a1=37, a2= a1-11 =37-11=26
a3= 48 -3*11=48-33=15 (using explicit formula),
and a3=a2 - 11=26 -11 =15 (the same answer)
Answer is B.
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Answer:
- <u><em>option D. ∠Y ≅ ∠B.</em></u>
Explanation:
Please, find attached the figure needed to answer this question.
<em>ASA </em>is the Angle-Side-Angle congruency rule. It states that if two angles and the included side of a triangle are congruent to two angles and the included side of other triangle, then, the two triangles are congruent.
In the figure it is given that the angle Z is congruent to the angle C, and the side CB is congruent to the side ZY.
Then, you need that the other angles B and Y be congruent too.
Thus, the answer is the option D. ∠Y ≅ ∠B.
In this way, you have two angles and the included side of one triangle are congruent to two angles and the included side of the other triangle.
- ∠Z ≅ ∠C
- ∠ Y ≅ ∠C
- segment CB ≅ ZY
Answer:
No
Step-by-step explanation:
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