I don't know how to solve number 6. Please help.
1 answer:
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32 × 2 = 68
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:
= 3.90625
32 × 3 = 96
32 × 4 = 128
So far we can conclude that the answer to your question lies somewhere between the numbers 3 and 4. To narrow down the answer some more, multiply 32 by 3.5 (a midway point between 3 and 4).
32 × 3.5 = 112
The number 112 tells us that the decimal we are looking for is higher than 3.5. (Because we need to get to 125, not 112.) Let's try some decimals between 3.5 and 4.
32 × 3.7 = 118.4
32 × 3.8 = 121.6
32 × 3.9 = 124.8
32 × 4 = 128
As we narrow down our answer, we can see that the number we are looking for lies between 3.9 and 4 on the number line. Now we need to start testing some decimals between 3.9 and 4.
32 × 3.905 = 124.96
Again, use the number five as a "midway" point to decide if you should use numbers that are higher or lower than 3.905. In this case, we need to use numbers higher than 3.905.
32 × 3.906 = 124.992
32 × 3.907 = 125.024
We are getting even closer to our number now that we know the decimal is somewhere between 3.906 and 3.907.
32 × 3.9065 = 125.008
With our midway point we can see that our number lies between 3.906 and 3.9065. Let's try a quarter point to see where our number lies from there.
32 × 3.90625 = 125
And BINGO! We have found the answer to the question. To be rephrased, our answer can be put like this:
Part a: The radius of the second sphere is 5 inches.
Part b: The volume of the second sphere is 523.33 in³
Part c; The radius of the third sphere is 1.875 inches.
Part d: The volume of the third sphere is 27.59 in³
Explanation:
Given that the radius of the sphere is 2.5 inches.
Part a: We need to determine the radius of the second sphere.
Given that the second sphere has twice the radius of the given sphere.
Radius of the second sphere = 2 × 2.5 = 5 inches
Thus, the radius of the second sphere is 5 inches.
Part b: we need to determine the volume of the second sphere.
The formula to find the volume of the sphere is given by
Substituting and
, we get,
Rounding off to two decimal places, we have,
Thus, the volume of the second sphere is 523.33 in³
Part c: We need to determine the radius of the third sphere
Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.
Hence, we have,
Diameter of the third sphere =
Radius of the third sphere =
Thus, the radius of the third sphere is 1.875 inches
Part d: We need to determine the volume of the third sphere
The formula to find the volume of the sphere is given by
Substituting and
, we get,
Rounding off to two decimal places, we have,
Thus, the volume of the third sphere is 27.59 in³