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Galina-37 [17]
4 years ago
8

What is the domain and range for y=sqrt(x-4)?

Mathematics
1 answer:
Lesechka [4]4 years ago
6 0

Domain: set of all numbers that can be inputted into a function

Since you cannot take the square root of a negative number, this means that x-4 CANNOT be negative. So it's either 0 or it's positive.
So.. <span>x−4≥0
</span>x−4+4≥0+<span>4
</span>x≥<span>4

</span>So this says: "Any number greater than or equal to 4 will result in x-4 being either 0 or some positive number"
So this means that the domain is

<span>{x|x≥4}

</span>This basically says: "the domain is the set of all numbers x such that x is greater than or equal to 4"

In interval notation, the domain is <span>[4,∞)


</span>The range is the set of all possible outputs. We can find the most extreme point of the range by plugging in the most extreme value for the domain <span>
sqrt(x-4) = </span>sqrt(4-4) = <span>sqrt(0) = 0

</span>So the smallest possible output is y=0, which means that the range is
<span>{y|y≥0<span>}
</span></span>
This basically says: "the range is the set of all numbers y such that y is greater than or equal to 0"

In interval notation, the range is

<span>[0,∞)</span>

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