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Galina-37 [17]
4 years ago
8

What is the domain and range for y=sqrt(x-4)?

Mathematics
1 answer:
Lesechka [4]4 years ago
6 0

Domain: set of all numbers that can be inputted into a function

Since you cannot take the square root of a negative number, this means that x-4 CANNOT be negative. So it's either 0 or it's positive.
So.. <span>x−4≥0
</span>x−4+4≥0+<span>4
</span>x≥<span>4

</span>So this says: "Any number greater than or equal to 4 will result in x-4 being either 0 or some positive number"
So this means that the domain is

<span>{x|x≥4}

</span>This basically says: "the domain is the set of all numbers x such that x is greater than or equal to 4"

In interval notation, the domain is <span>[4,∞)


</span>The range is the set of all possible outputs. We can find the most extreme point of the range by plugging in the most extreme value for the domain <span>
sqrt(x-4) = </span>sqrt(4-4) = <span>sqrt(0) = 0

</span>So the smallest possible output is y=0, which means that the range is
<span>{y|y≥0<span>}
</span></span>
This basically says: "the range is the set of all numbers y such that y is greater than or equal to 0"

In interval notation, the range is

<span>[0,∞)</span>

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Please help ASAP !! :)
Mila [183]

Answer:

  1. temperature is decreasing as time passes
  2. x-axis
  3. hot drink temperature (°C)

Step-by-step explanation:

1. Each value of temperature is lower than the one previous, so we can say the temperature is decreasing. We also notice that the rate of decrease is getting smaller, possibly because the temperature is approaching a horizontal asymptote.

__

2. The horizontal axis, where temperature is plotted, is conventionally called the x-axis.

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3. The label on the vertical axis is "temperature" and the graph title is "cooling a hot drink ...", so we presume the dependent variable is the temperature of a hot drink.

7 0
4 years ago
This doesn’t make sense explain plz
AnnZ [28]

Its simple, graph them.

For the first equation, go on the Y-Axis (the vertical one) and go to 4. Then from there go up 1, right 6.

For the second equation go on the Y-Axis (the vertical one) and plot a point at 1 (aka 0,1) Now you go up 1, right 3.

When you see an equation like y=2x+3, the 3 represents the point (0,3) as when the x is 0, y=3. Just plug the numbers in. And as for the "2x" 2 is the slope. Slope is always rise/run or up, then right. So if its 2 your slope is 2/1, rise 2, over 1. If it "-2x" is your slope then all you have to do is go down 2, right 1.

I hope this cleared up your confusion, brainliest/heart would help.

5 0
3 years ago
Parallelogram ABCD is dilated to form parallelogram WXYZ. What corresponding side is proportional to segment AD? Type the answer
Reika [66]

Answer: WZ

The sequence ABCD has AD as the first and last letters of that sequence, so this pattern applies to WXYZ as well to pull out WZ. Angle A pairs up with angle W because they are both the first letters of the sequences. These angles are congruent from the fact that the parallelograms are similar. The same can be said for angle D and angle Z.

note: WZ is the same as ZW. The order doesn't matter when it comes to labeling segments based on endpoints.

6 0
3 years ago
What is the average of 1/4 and 6/18
galina1969 [7]

Answer:

7/24

Step-by-step explanation:

(1/4+6/18)/2=7/24

8 0
3 years ago
If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's ru
aleksandrvk [35]

Answer:

Step-by-step explanation:

If a sequence c1,c2,c3,...has limit K then the sequence ec1,ec2,ec3,...has limit e^K. Use this fact together with l'Hopital's rule to compute the limit of the sequence given by

bn=(n)^(5.6/n).

a)

L =  \lim_{n \to \infty} b_n \\\\\\L= \lim_{n \to \infty} n^{\frac{5.6}{n} }

Log on both sides

In (L) =  \lim_{n \to \infty} In (n)^{\frac{5.6}{n} }\\\\= \lim_{n \to \infty} \frac{5.6}{n} In(n)

=5.6 \lim_{n \to \infty} \frac{d}{dn}  In(n)/\frac{d}{dn} (n)\\\\=5.6 \lim_{n \to \infty} \frac{1}{n} /1 \\\\=5.6 \lim_{n \to \infty} \frac{1}{n} \\\\=5.6 \times 0\\\\In(L) =0\\\\L=e^0\\\\L=1

\therefore  \lim_{n \to \infty} (n)^{\frac{5.6}{n} =1

5 0
4 years ago
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