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3 years ago

3x+3y=36 X=y+2 Solve the system of equations

Mathematics

1 answer:

Nesterboy [21]3 years ago

5 0

Step-by-step explanation:

I don't know

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Judah walks 6/8 of a miles every day. How many miles does Judah walk in 5 days

Sladkaya [172]

3 3/4 miles, because 6*5=30, so 30/8= 3 6/8, which equals 3 3/4 miles.

6 0

4 years ago

Help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am

zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

${\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}$

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ a = 1 , b = - 10 , c = 27

Now , Calculating D ;

${:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}$

${:\implies \quad \sf D=100-108}$

${:\implies \quad \bf \therefore \quad D=-8}$

Now , Calculating the vertex ;

${:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}$

${:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}$

${:\implies \quad \bf \therefore \quad Vertex = (5,2)}$

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

5 0

3 years ago

The dot plot shows how many swimmers are in each line at a waterpark: Dot plot titled Swimmers in Line and labeled Number of Swi

nasty-shy [4]

The answer is median, because the data is skewed and there is an outlier.

3 0

3 years ago

Read 2 more answers

Greatfull in advance :)

nydimaria [60]

Answer:

160 m

Step-by-step explanation:

For the 15-deg angle, h is the opposite leg.

The hypotenuse is 628 m.

The trigonometry ratio that relates the opposite leg and the hypotenuse is the sine.

sin A = opp/hyp

$\sin 15^\circ = \dfrac{h}{628~m}$

$h = 628~m \times \sin 15^\circ$

$h = 162.54~m$

Rounded to 2 significant figures:

h = 160 m

5 0

3 years ago

A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 128 million kilometers.

Jet001 [13]

The answer for this problem would be:

Orbital period if distance = 128,000,00 km and mass = Sun?

This is approximately be .85 astronomical units if converted km to au.

We will be using Kepler's third law which is:

T^2 = r^3 

T^2 = .85^3 

T^2 = .61

get the square root of .61
so the answer will be:

T = .78 Years which is in months is 9.36 months.

3 0

3 years ago