The correct answer for the question that is being presented above is this one: "A. 960."<span>Four different sets of objects contain 2, 5, 6, and 7 objects, respectively.
</span>
= 2 * 5 * 6 * 7
= 960
Here are the following choices:
A. 960
<span>B. 141 </span>
<span>C. 23 </span>
D. 529
Answer:
z−181=−170
Step 1: Add 181 to both sides.
z−181+181= −170+181
z=11
<span>let
x = acres of when
y = acres of rye
Maximize
z = 500x + 300y
subject to
x >= 3
x <= 15
y >= 1
y <= 7
x + y <= 20
bounded
both
(3, 1)
(15, 1)
(15, 5)
(13, 7)
(7, 3)
sub points into your max equation
(3, 1) = 1500 + 300 = 1800
(15, 1) = 7500 + 300 = 7800
(15, 5) = 7500 + 1500 = 9000
(13, 7) = 6500 + 2100 = 8600
(7, 3) = 3500 + 900 = 4400
max profit of $9,000 is achieved when 15 acres of wheat and 5 acres of rye are planted and sold</span>
Answer:
18
Step-by-step explanation:
median is the number in the middle of the set of numbers