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3 years ago

Please help! Which are acceptable names for the line?

Mathematics

2 answers:

lesya692 [45]3 years ago

8 0

so answers B and C are correct, but D isn't
and just thinking about it B can't be correct either because it has a point on a line and letter A i constructed a new red plane that also have AU thus AU is not unique so im goining with (C)

serg [7]3 years ago

6 0

'B' and 'D' are correct.
'C' isn't, and we don't know about 'A' because you left it out.

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Suppose the number of dropped footballs for a wide receiver over the course of a season are normally distributed with a mean of

snow_lady [41]

Answer:

The z score for a wide receiver who dropped 13 footballs over the course of a season

Z = - 1.5

Step-by-step explanation:

Explanation:-

Given Population mean ' μ'= 16

Standard deviation of Population 'σ' = 2

Let 'x' be the Random Variable of Normal distribution

Given x = 13 foot balls

The z score for a wide receiver who dropped 13 footballs over the course of a season

$Z = \frac{x-mean}{S.D}$

$Z = \frac{13 -16}{2} = \frac{-3}{2} = -1.5$

Final answer:-

The z score for a wide receiver who dropped 13 footballs over the course of a season

Z = - 1.5

8 0

3 years ago

.........plz help...........

Leya [2.2K]

Answer:

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Step-by-step explanation:

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4 years ago

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The angle o represents the phase shift, determined by the initial conditions of the experiment or the position of the weight at

lbvjy [14]

Answer:

Step-by-step explanation:

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3 years ago

If there are 4 apples take away 1 how many apples are there

igor_vitrenko [27]

3 apples

You need to subtract 1 from the total 4 bringing you to 3
4-3=1

5 0

3 years ago

A missile protection system consists of n radar sets operating independently, each with probability 0.9 of detecting a missile e

stepladder [879]

Answer:

A.) The probability that the missile is not detected by any of n sets = (1-0.9)^n = 0.1^n.

Where it's opposite will be that the missile is detected by atleast 1 of the sets. Which will be equals to 1-(0.1)^n.

B.) 0.999= 1-(0.1)^n

Here n=3

For, 0.999999=1-(0.1)^n

n=6.

C.) If n=5

5C4*(0.9)^4*(0.1)^1= 0.32805

6 0

3 years ago