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Dafna11 [192]
3 years ago
15

Which equation can be used to solve for x in the following diagram? pls help

Mathematics
2 answers:
Cloud [144]3 years ago
8 0

Answer:b

Step-by-step explanation:

VladimirAG [237]3 years ago
4 0
Answer:
7x + 11x = 90
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Use the formula to determine the area of squares with side lengths of 3 cm, 10.5 cm, and π cm.
Nataliya [291]

Answer:

For length of side = 3 cm

Area of the square = 9 cm²

For length of side = 10.5 cm

Area of the square =  110.25 cm²

For length of side = π cm

Area of the square = 9.869 cm²

Step-by-step explanation:

The area of a square is given as :

Area = Side²

therefore,

For length of side = 3 cm

Area of the square = ( 3 cm )² = ( 3 × 3 ) cm² = 9 cm²

For length of side = 10.5 cm

Area of the square = ( 10.5 cm )² = ( 10.5 × 10.5 ) cm² = 110.25 cm²

For length of side = π cm

Area of the square = ( π cm )²  

= ( π × π ) cm²                

= 3.14² cm²                                [π = 3.14]

= 9.869 cm²

8 0
3 years ago
How can you use number patterns to find the least common factor
Aleks04 [339]

Answer:

The correct answer is: 360.

Explanation:

First we can express 120 as follows:

2 * 2 * 2 * 3 * 5 = 120

You can get the above multiples as follows:

120/2 = 60

60/2 =30

30/2 = 15

15/3 = 5 (Since 15 cannot be divisible by 2, so we move to the next number)

5/5 = 1

Take all the terms in the denominator for 120, you would get: 2 * 2 * 2 * 3 * 5 --- (1)

Second we can express 360 as follows:

360/2 = 180

180/2 = 90

90/2 =45

45/3 = 15 (Since 45 cannot be divisible by 2, so we move to the next number)

15/3 = 5

5/5 = 1

Take all the terms in the denominator for 360, you would get: 2 * 2 * 2 * 3 * 3 * 5 --- (2)

Now in (1) and (2) consider the common terms once and multiple that with the remaining:

2*2*2*3*5 = Common between the two

3 = Remaining

Hence (2*2*2*3*5) * (3) = 360 = LCM (answer)

5 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(x-16)^{\circ}∠A=(x−16) ∘ and m\angle B=(3x+28)^{\circ}∠B=(3x+28) ∘ , t
GalinKa [24]

Answer:

  ∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

  ∠A +∠B = 180°

  (x -16)° +(3x +28)° = 180°

  4x° + 12° = 180°

  x° +3° = 45°

  x° = 42°

  ∠A = (x -16)° = 42° -16°

  ∠A = 26°

3 0
3 years ago
Any one help me with this plsss and ni links plss!!
Bas_tet [7]

Answer:

6. D.

7.  F.

8. A.

9. B.

10. C.

Step-by-step explanation:

6.     9 + (12 - 10)

       12 - 10 = 2

        9 + 2 = 11

7.      (20 - 15) x 2

        20 - 15 = 5

         5 x 2 = 10

8.      10 ÷ 5 + 7

         10 ÷ 5 = 2

          2 + 7 = 9

9.        6 + 2 x 3

           2 x 3 = 6

           6 + 6 = 12

10.        (2 x 4) + 8

             2 x 4 = 8

             8 + 8 = 16

Let me know if this helps!

4 0
2 years ago
Find the volume of a right prism with height h=10 cm, if :
kozerog [31]

Answer:

Step-by-step explanation:

          So, to begin the altitude of a triangle is the line segment that starts at the top vertex and ends at the base of the triangle forming a right angle. If we want to find the volume of the of the prism the formula is Ab*h. This is the area of the base, times the height of the prism. This is true because a simple expination of volume is a box filled with stuff. To count how much stuff we have in the box the formula uses layers. Volume is just like a lot of 2 dimential areas stacked on top of each other. So taking the area of the flat base and puting it on top of it self 10 time will give you the same prism thats in the problem. Now we just have to apply the consept. Since the base is a triangle and we need to find the area. The formula is b*h*1/2. Base time height times 1/2. The reason for this is also simlar to area. A triangle is half of a square, so to find the area of a square the formula is L*W. Since a triangle is half of a square you just multipuly it by 1/2. When solved you will get 4*3.5*1/2=7, the area of the base is 7 cm^2. Now appling the topic above we stack the base 10 times, so 7*10=70. In conculstion the volume of the prism would be 70 cm^2.

6 0
2 years ago
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