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LUCKY_DIMON [66]
3 years ago
7

Suppose the number of dropped footballs for a wide receiver over the course of a season are normally distributed with a mean of

16 and a standard deviation of 2. What is the z score for a wide reciever who dropped 13 footballs over the course of a season ?
Mathematics
1 answer:
snow_lady [41]3 years ago
8 0

Answer:

<em>The z score for a wide receiver who dropped 13 footballs over the course of a season</em>

<em>           Z = - 1.5</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given Population mean  ' μ'= 16

Standard deviation of Population 'σ' = 2

Let 'x' be the Random Variable of Normal distribution

Given x = 13 foot balls

<em>The z score for a wide receiver who dropped 13 footballs over the course of a season</em>

<em>                 </em>Z = \frac{x-mean}{S.D}<em></em>

<em>                </em>Z = \frac{13 -16}{2} = \frac{-3}{2} = -1.5<em></em>

<u><em>Final answer</em></u><em>:-</em>

<em>The z score for a wide receiver who dropped 13 footballs over the course of a season</em>

<em>           Z = - 1.5</em>

<em></em>

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1. Regroup terms
x(x+5)=104

2. Expand
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3. Move all terms to one side
x^2+5x-104=0

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Since x<0 is not possible in this case, x=8

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