To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children
5a + 2c = 1,220
a + c = 295
a + c = 295
-c -c
a = 295 - c
5(295 - c) + 2c = 1,220
1,475 - 5c + 2c = 1,220
1,475 - 3c = 1,220
1,475 - 3c = 1,220
-1,475 -1,475
-3c = -255
-3c/-3 = -255/-3
c = 85
a + c = 295
a + 85 = 295
-85 -85
a = 210
210 adults attended the dance recital
Hope this helps!
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
sin s = 36 / 42 = 18 / 21 = 6/ 7
sin R = 14 / 42 = 7 / 21 = 1 / 3
cos s = 14 / 42 = 1 / 3
cos R = 36 / 42 = 6 / 7