Let x be the number of racing bikes, and let y be the number of mountain bikes.
1) 140x + 110y = 26150
2) 180x + 120y = 31800
Solve for one of the variables and plug that in to the other equation:
From equation 1: 140x = 26150 - 110y
x = (26150-110y)/140
Plug this into equation 2:
180((26150-110y)/140) = 31800
Solve for y, and find that y = 85 (the number of mountain bikes).
Plug that y into either equation to find x:
140x + 110(85) = 26150
x = 120 (the number of racing bikes).
So the answer is: 120 racing bikes and 85 mountain bikes.
Answer:
B.) -⅔
Step-by-step explanation:
Subtract each variable
y¹-y
x¹-x
-2-4 = -6
4-(-5) = 9 -6/9 = -⅔
A because the starting values is not a negative
We are given with the expression <span> B = 703 * w / h^2. To isolate w in the function, we multiply the whole equation by h^2. This results to B h^2 = 703 w. Next, we divide the equation by 703 to isolate w. The final expression of w becomes w = B h^2 / 703 </span>
Answer:
Step-by-step explanation:
(a) You use the fact that the lengths RS and ST total the length RT.
RS +ST = RT
(6y+3) +(3y+5) = 80 . . . . . substitute the given values
9y +8 = 80 . . . . . . . . . . . . .simplify
9y = 72 . . . . . . . . . . . . . . . .subtract 8
72/9 = y = 8 . . . . . . . . . . . .divide by the coefficient of y
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(b) Now, the value of y can be substituted into the expressions for RS and ST to find their lengths.
RS = 6y +3 = 6·8 +3
RS = 51
ST = 3y +5 = 3·8 +5
ST = 29
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<em>Check</em>
RS +ST = 51 +29 = 80 = RT . . . . the numbers check OK
