there are 12 inches in 1 foot, so 6 inches is really just half a foot, thus 3'6" is really just 3.5' or 3½ feet.
now, let's convert those mixed fractions to improper fractions and then subtract, bearing in mind our LCD will be 8.
![\bf \stackrel{mixed}{4\frac{5}{8}}\implies \cfrac{4\cdot 8+5}{8}\implies \stackrel{improper}{\cfrac{45}{8}}~\hfill \stackrel{mixed}{3\frac{1}{2}}\implies \cfrac{3\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{7}{2}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{45}{8}-\cfrac{7}{2}\implies \stackrel{\textit{using the LCD of 8}}{\cfrac{(1)45~~-~~(4)7}{8}}\implies \cfrac{45-28}{8}\implies \cfrac{17}{8}\implies 2\frac{1}{8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B5%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%208%2B5%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B45%7D%7B8%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B2%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%202%2B1%7D%7B2%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B7%7D%7B2%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B45%7D%7B8%7D-%5Ccfrac%7B7%7D%7B2%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%208%7D%7D%7B%5Ccfrac%7B%281%2945~~-~~%284%297%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B45-28%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B17%7D%7B8%7D%5Cimplies%202%5Cfrac%7B1%7D%7B8%7D)
Step-by-step explanation:
for mean w. you have to add up all the values (cat weights) and divide them by the number of cats
and for median w. you need to compare the values from the smallest to the largest and cross out the numbers from the ends. Since there are 6 cats here (odd number) you will have 2 values left. Add them up and divide them by 2 (since there are 2)
Answer:
100,650
Step-by-step explanation:
Answer:
The correct options are 1,2 and 3.
Step by step explanation:
According to the definition of function there exist unique value of y for each value of x in the domain of the function.
If equation have more than one values of y for any value of x, then the equation is not a function.
.... (1)
... (2)
A quadratic equation have two values of x and the value of y can be any number. So a quadratic equation is not a function.
The first and second equations are quadratic equations so the equation (1) and (2) are not functions.
The third equation is

The degree of y is 2. It means for each value of x there exist two values of y.
Put x=0, then we get

More than one values of y exist for single value of x.
So the equation (3) is not a function.
The fourth equation is

Since the degree of x is 1 and degree of y is also 1, therefore it is a linear equation and for each value of x there exist a unique value of y.
Therefore the equation (4) is a function.