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Inessa05 [86]
3 years ago
10

Help pleas brainliest is insured if correct

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

9 units

Step-by-step explanation:

because if the y-axis is 5 and the x-axis is 9, the line is 9 units.

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i need help. Semir, Sarah, and SungSo decided to raise money for a local homeless shelter by working in a local deli. The deli a
IgorLugansk [536]
According to the question, 
Let,
"n" represent the number of miles semir walked.
"y" represent the number of miles sarah walked.
Now, according to the question,

y = 2n - 5  ........................this is your equation 
Also,
the question states, each of them collect $18 in pledges for every miles walked.

Given,
Sarah collected $450
Now, 

Using unitary method,

Sarah collects $18 for 1 mile
Sarah collects $1 for (1 / $18) mile
Sarah collects $450 for (1 / 18) * 450 mile
                                   = 25 miles
So, Sarah walks 25 miles.
Now,
Taking equation,
y = 2n - 5
Since, y is the no. of miles sarah walked, we can write 25 in place of "y" So,
(25) = 2n - 5
25 + 5 = 2n
30 = 2n
30 / 2 = n
15 = n

Since, "n" is the no. of miles that semir walked, Semir walked 15 miles.


7 0
3 years ago
The function f(t) = 180(1.01) 6 represents the change in a quantity over i years.
lesya692 [45]

Step-by-step explanation:

3 divide 180 230 7 c=mc square that eaquls 2

8 0
3 years ago
Suppose <img src="https://tex.z-dn.net/?f=m" id="TexFormula1" title="m" alt="m" align="absmiddle" class="latex-formula"> men and
ollegr [7]

Firstly, we'll fix the postions where the n women will be. We have n! forms to do that. So, we'll obtain a row like:

\underbrace{\underline{~~~}}_{x_2}W_2 \underbrace{\underline{~~~}}_{x_3}W_3 \underbrace{\underline{~~~}}_{x_4}... \underbrace{\underline{~~~}}_{x_n}W_n \underbrace{\underline{~~~}}_{x_{n+1}}

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m~~~(i)

Since there is no women sitting together, we must write that x_2,x_3,...,x_{n-1},x_n\ge1. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

\begin{cases}x_2=x_2'+1\\x_3=x_3'+1\\...\\x_{n-1}=x_{n-1}'+1\\x_n=x_n'+1\end{cases}

The equation (i) can be rewritten as:

x_1+x_2+x_3+...+x_{n-1}+x_n+x_{n+1}=m\\\\&#10;x_1+(x_2'+1)+(x_3'+1)+...+(x_{n-1}'+1)+x_n+x_{n+1}=m\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-(n-1)\\\\&#10;x_1+x_2'+x_3'+...+x_{n-1}'+x_n+x_{n+1}=m-n+1~~~(ii)

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: \dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}

[I can write the proof if you want]

Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: m!

Multiplying all results:

n!\times\dfrac{(m+1)!}{n!(m-n+1)!}\times m!\\\\&#10;\boxed{\boxed{\dfrac{m!(m+1)!}{(m-n+1)!}}}

4 0
3 years ago
I need help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vichka [17]

112 m³

the solid is a rectangular pyramid with volume (V)

V = \frac{1}{3} × area of base × height = \frac{1}{3} × (8 × 4.2 ) × 10 = 112 m³



4 0
3 years ago
Is 0, 2, 4, 6, a arithmetic sequence
amid [387]
Yes, 0 + 2 = 2
2 + 2 = 4
4 + 2 = 6.
Since they're just ADDING 2, not MULTIPLYING by 2, it's arithmetic, not geometric.
6 0
3 years ago
Read 2 more answers
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