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Tidwell Industries has the following overhead costs and cost drivers. Direct labor hours are estimated at 100000 for the year. A

Darya [45]

Answer:

Overhead rate for ordering and receiving = $300 per order.

Explanation:

Given Activity costs and activity drivers

Activity Overhead Cost Driver Activity

Ordering & Receiving Order $150,000 500 orders

Machine Setup $324,000 450 setups

Machining $1,587,500 125,000 MH

Assembly Parts $1,260,000 1,000,000 parts

Inspection $330,000 500 inspections

Under activity based costing the rates are based on the nature of activity and the rates are based on number of those activities per driver. As for ordering and receiving there are total of 500 orders and total cost = $150,000 that is cost per order will be computed.

Overhead rate for ordering and receiving = $150,000/500 orders = $300 per order.

6 0

3 years ago

On January 1, 2018, Tyson Manufacturing Corporation purchased a machine for $40,000,000. Tyson's management expects to use the

enyata [817]

Answer:

$4,842,800.00

Explanation:

Units-of-production depreciation method calculates the amount to be deprecation depending on the asset usage for that period.

In this case, the total hours the asset is expected to work.

Cost of machine $ 40,000,000.00

Salvage value : $ 47,000.00

total hours machine should work: 33,000.00

Depreciable amount: = Cost price- salvage value

=$40,000,000.00-$47,000.00

=$39,953,000.00

Depreciation per hour= $39,953,000.00/33000

=1,210.6969

=1,210.70

Depreciation for 2018 =1210.7x4000

=$4,842,800.00

5 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Sonbull [250]

Answers:

F h Garvey

Explanation:

Dfffd

4 0

2 years ago

Why do you look like dababy?

olasank [31]

Letsss gooo you know it’s baby

7 0

2 years ago

Read 2 more answers

you have $6000 to invest in two stock funds. The first fund pays 5% annual interest and the second account pays 9% annual intere

stira [4]

Answer:

Amount of money invested is $2,000 and $4,000

Explanation:

In this question, we are asked to calculate how much was invested in two different accounts given the amount of money invested in both accounts.

Let the amount of money invested in both accounts be a and b respectively.

Mathematically;

A + B = 6000 ......I

Now we use the formula for simple interest to check the amount that is supposed to be made on Both accounts if he end of a year.

Formula for simple interest is I = PRT/100

Let’s apply this to what is on ground:

5*1* a/100 = 5a/100

Second is

9*b*1/100 = 9b/100

That is 5a + 9b = 38,000. ........ii

Solving Both simultaneously as follows:

Let A = 6000-b from 1

Substitute this into 2

5(6000-b) + 9b = 38,000

30,000 -5b + 9b = 38,000

4b = 8,000

b =$2000

This means a would be 6000 - 2,000 = $4000

8 0

3 years ago