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3 years ago

Given that ABCD is a rhombus, what is the value of x? (3x + 12

Mathematics

1 answer:

Alex777 [14]3 years ago

3 0

Answer:

19.5

is the correct answer

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Which numbers are solutions to the inequality below?

babunello [35]

Answer:

4, 5 and 6

Step-by-step explanation:

Add 19 to both sides:

-4x > 52

Divide by -4

x > -13 (Flip the sign when multiplying or diving by a negative)

4, 5 and 6 satisfy this

6 0

3 years ago

Can someone please help me?

Flauer [41]

C) You have to subtract3x from x yielding -2x.

7 0

3 years ago

(Picture) INFINITE SEQUENCES AND SERIES PLEASE HELP!!

mojhsa [17]

Answer:

C) $x=\frac{17}{33}$

Step-by-step explanation:

0.51 repeating decimal

x= 0.51515151

multiply by 100 on both sides

100x = 51.515151.........

x= 0.515151...............

--------------------------------------------(subtract)

99x = 51

divide by 99 on both sides

$x=\frac{51}{99}$

divide both sides by 3

$x=\frac{17}{33}$

5 0

3 years ago

A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live

RSB [31]

Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

$f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}} \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.$

So the marginal function for X is given as

$f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}$

Now

$f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }$

Now the value of E(Y/X) is given as

$E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2$

So the value of E(Y/X) is 2.

3 0

3 years ago

Help me please I forgot my notes at school

sukhopar [10]

1/2 x 6 = 3
3 x 8 = 24
24/6 = 4
4 - 1 = 3

3 is your answer

hope this helps

6 0

3 years ago

Read 2 more answers