It’s a little surprising that this question didn’t come up earlier. Unfortunately, there’s no intuitive way to understand why “the energy of the rest mass of an object is equal to the rest mass times the speed of light squared” (E=MC2). A complete derivation/proof includes a fair chunk of math (in the second half of this post), a decent understanding of relativity, and (most important) experimental verification.
Answer:
2
Step-by-step explanation:
Replace t with 6:
g(t) = 2(t-3)-4 becomes g(6) = 2(6-3)-4 = 2(3) - 4 = 6 - 4 = 2
Answer:
5.19
Step-by-step explanation:
3 rounds down to 0
5.190
5.19 is to the 100th
Answer:
Step-by-step explanation:
6x + 3y = -18
Taking 3 common from left side
so, 3(2x+y) = -18
2x+y = -18/3
2x+y = -6 (equation 1)
and, 7x + 7y = 0
Taking 7 as commom from left side
7(x + y) = 0
x + y = 0/7
x + y = 0 (equation 2)
now , by using elimination method
subtracting equation2 from equation1
2x + y - (x + y)= -6 - 0
2x + y - x - y = -6
x = -6
so, x = -6
substituting value of x in equation 1
2(-6) + y = -6
-12 + y = -6
y = -6 +12
y = 6
hence, the value of x = -6
and value of y = 6
